Acceleration Due To Gravity

If a tunnel is cut at any orientation through the earth, then a ball released from one end will reach the other end in how much time (neglect earth rotation)? 

Gravitational force on point mass in side solid sphere.

(i) When a point mass $m$ is considered at distance $r$ from the centre of solid sphere inside it then gravitational force on point mass is proportional to.

If the radius of the earth were to shrink by one percent, its mass remaining same, the value of $\mathrm{g}$ on the earths surface would

Weight of an object can be explained as                                                                         

Acceleration due to gravity at a height of $h$ is $25\%$ of that at the surface of the Earth. The value of $h$ in terms of radius of earth $R$ is
radius of the Earth. 

The mass and density of the moon, if acceleration due to gravity on its surface is $1.62 \mathrm{m} {\mathrm{s}}^{-2}$ and its radius is $1.74\times {10}^6 \mathrm{m}$, respectively. $($Take, $G=6.67\times {10}^{-11} \mathrm{N}-{\mathrm{m}}^2 {\mathrm{kg}}^{-2}$)

Two planets have the same average density but their radii are $R_1$ and $R_2.$ If acceleration due to gravity on these planets be $g_1$ and  $g_2$ respectively, then :-

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is $R,$ the radius of the planet would be

The force of attraction due to a hollow spherical shell of uniform density on a point mass situated inside it is zero.

What is the force of attraction between a hollow spherical shell of uniform density and a point mass located inside the shell?

What is the direction of gravitational force between a hollow spherical shell of uniform density and a point mass situated outside the shell?

The force of attraction between a hollow spherical shell of uniform density and a point mass situated outside is just as if the entire mass of the shell is concentrated at the _____ of the shell.

The force of attraction due to a hollow spherical shell of uniform density on a point mass situated outside is zero.

The acceleration due to gravity on the earth's surface is 

The value of acceleration due to gravity is maximum at ____.

Weight of an object can be explained as                                                                         

What is acceleration due to gravity at the surface of mars if its diameter is $6760 \mathrm{km}$ and mass one tength that of earth. The diameter of earth is $12742 \mathrm{km}$ and acceleration due to gravity on earth is $9.8 \mathrm{m}/{\sec }^2$ 
 

Gravitational potential $V$ versus distance $r$ graph is represented in figure. The magnitude of gravitational field intensity is equal to:

The density of two planets are in ratio $1:2$ and their radii are in the ratio $3:2$ . The acceleration due to gravity on the surface of planets are in the ratio

$R$ is the radius of Earth and $\omega$ is its angular velocity and $g_p$ is the value of $g$ at the poles. The effective value of $g$ at a latitude $\lambda ={60}^o.$